Biology Biomolecules NUMS 2024
PMDC Verified Question 10 of 142
Less reactivity of sucrose is due to its:
A
High solubility in water
B
Polar nature
C
Unavailability of functional group
D
1-2 glycosidic linkage
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: Unavailability of functional group
Concept:

Chemical reactivity in sugars is dictated by the availability of a free, unbonded anomeric carbon (the reducing end).

Solution:

  • To be a reactive "reducing sugar" (capable of reacting with Benedict's or Tollens' reagent), a sugar must have a free aldehyde or ketone group that can open up from the ring structure.


  • In Sucrose, the highly reactive anomeric carbon of glucose (C1) is covalently bonded directly to the highly reactive anomeric carbon of fructose (C2).


  • Because both functional groups are entirely locked up in this unique \(\alpha-1,2\) bond, the molecule has absolutely no free functional ends.


  • This complete unavailability of functional groups makes sucrose non-reducing, highly stable, and exceptionally unreactive (perfect for safe transport in plant sap).


Why other options are incorrect:

  • 1-2 glycosidic linkage: While this is the cause of the unavailability, the direct chemical reason for the lack of reactivity itself is the literal "unavailability of the functional group". Both C and D are technically related, but C describes the fundamental chemical mechanism.


  • High solubility / Polar nature: Physical properties unrelated to chemical redox reactivity.

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