Chemistry Alcohols & Phenols ETEA 2016
PMDC Verified Question 83 of 95
Choose reaction that does not require \(\text{ZnCl}_2\) Catalyst:
A
\(\text{CH}_3\text{CH}_2\text{OH} + \text{HCl} \longrightarrow \text{CH}_3\text{CH}_2\text{Cl} + \text{H}_2\text{O}\)
B
\(\text{CH}_3\text{CH}_2\text{OH} + \text{HBr} \longrightarrow \text{CH}_3\text{CH}_2\text{Br} + \text{H}_2\text{O}\)
C
\(\text{CH}_3\text{CH}_2\text{OH} + \text{HI} \longrightarrow \text{CH}_3\text{CH}_2\text{I} + \text{H}_2\text{O}\)
D
Both B & C
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: Both B & C
Concept:

The reactivity of halogen acids with alcohols follows the order HI > HBr > HCl, based on bond dissociation energy and the strength of the acid.

Formula:

Not applicable to this conceptual question.

Solution:

  • HCl is relatively unreactive with primary alcohols and explicitly requires a Lewis acid catalyst like anhydrous \(\text{ZnCl}_2\) (Lucas reagent) to weaken the C-O bond.


  • HBr and HI are much stronger acids and more reactive; they can protonate and substitute the alcohol without requiring the \(\text{ZnCl}_2\) catalyst.


  • Therefore, reactions B and C do not require the catalyst.


Why other options are incorrect:

Option A is the only reaction that does require the catalyst. Thus, choosing "Both B & C" is the complete and correct answer.

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