Chemistry Alcohols & Phenols DUHS 2022
PMDC Verified Question 48 of 95
Oxidation of primary alcohol gives:
A
Aldehyde
B
Ketone
C
Alkane
D
Alkene
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: Aldehyde
Concept:

The mild oxidation of a primary alcohol removes two hydrogen atoms (one from the hydroxyl group, one from the alpha-carbon) to form a carbon-oxygen double bond at the terminal carbon.

Formula:

$$ \text{R-CH}_2\text{OH} \xrightarrow{[O]} \text{R-CHO} + \text{H}_2\text{O} $$

Solution:

  • A primary alcohol has its -OH group on a terminal carbon.


  • Removing the hydrogens creates a carbonyl group (C=O) bonded to at least one hydrogen atom.


  • This specific functional group arrangement defines an aldehyde.


Why other options are incorrect:

Ketones are formed from the oxidation of secondary alcohols. Alkanes and alkenes are hydrocarbons (containing no oxygen), requiring reduction or dehydration processes, not oxidation.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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