Chemistry Alcohols & Phenols ETEA 2023
PMDC Verified Question 27 of 95
Ethyl alcohol in the presence of \(\text{H}_2\text{SO}_4\) at 170°C produces:
A
Ether
B
Ethene
C
Ester
D
Ethane
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: Ethene
Concept:

At elevated temperatures, concentrated sulfuric acid acts as a powerful dehydrating agent, forcing an intramolecular elimination (\(\beta\)-elimination) reaction.

Formula:

$$ \text{CH}_3\text{-CH}_2\text{OH} \xrightarrow[170^{\circ}\text{C}]{\text{Conc. H}_2\text{SO}_4} \text{CH}_2\text{=CH}_2 + \text{H}_2\text{O} $$

Solution:

  • The high temperature (170°C) provides enough activation energy to cleave both the C-OH bond and a C-H bond on the adjacent beta-carbon of the same molecule.


  • A carbon-carbon double bond forms to satisfy valency, yielding an alkene.


  • For ethyl alcohol, the resulting alkene is ethene.


Why other options are incorrect:

Ether is formed at lower temperatures (140°C). Esterification requires a carboxylic acid. Ethane requires reduction (hydrogenation), not dehydration.

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