Chemistry Atomic Structure MDCAT 2013
PMDC Verified Question 91 of 95
Number of electrons in the outermost shell of chloride ion (\( \text{Cl}^- \)) is:
A
\( 17 \)
B
\( 7 \)
C
\( 8 \)
D
\( 1 \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: \( 8 \)
Concept: Formation of an anion involves the addition of electrons to the valence shell of a neutral atom to achieve a stable noble gas configuration.

Formula: $$ \text{Electrons} = Z - \text{Charge} $$

Solution:
  • A neutral Chlorine (Cl) atom has atomic number \( Z = 17 \).
  • Its electronic configuration is \( 1s^2, 2s^2, 2p^6, 3s^2, 3p^5 \) (or 2, 8, 7).
  • The outermost shell (\( n=3 \)) has \( 2 + 5 = 7 \) electrons.
  • When it gains 1 electron to form the chloride ion (\( \text{Cl}^- \)), the configuration becomes \( 3s^2, 3p^6 \).
  • The outermost shell now contains \( 2 + 6 = 8 \) electrons.


Why other options are incorrect: 17 is the total number of protons. 7 is the valence electrons in a neutral Cl atom, not the ion.

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