Chemistry Atomic Structure PMDC 2020
PMDC Verified Question 72 of 95
Quantum number values for "\(2p\)" orbitals are:
A
\( n=1, l=0 \)
B
\( n=2, l=1 \)
C
\( n=2, l=0 \)
D
\( n=1, l=2 \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( n=2, l=1 \)
Concept: Orbital nomenclature directly states the principal quantum number and uses a letter code for the azimuthal quantum number.

Formula: None required.

Solution:
  • The number "2" in "\(2p\)" denotes the principal quantum number: \( n = 2 \).
  • The letter "\(p\)" denotes the subshell type. The mapping is \( s=0, p=1, d=2, f=3 \).
  • Therefore, for a \(p\)-orbital, \( l = 1 \).
  • Result: \( n=2, l=1 \).


Why other options are incorrect: \(n=2, l=0\) is the \(2s\) orbital. The others denote \(1s\) or invalid states.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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