Chemistry Carboxylic Acids MDCAT 2011
PMDC Verified Question 88 of 94
\( \text{CH}_3\text{CN} + \text{HCl} \longrightarrow \text{A} + \text{B} \) in presence of water in the above reaction A and B are:
A
Acetic acid and acid amide
B
Acetic acid and methyl chloride
C
Acetic acid and ammonia
D
Acetic acid and ammonium chloride
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: Acetic acid and ammonium chloride
Concept:

The acid-catalyzed hydrolysis of an alkyl nitrile (methyl cyanide) yields a carboxylic acid and an ammonium salt.

Formula:

$$ \text{CH}_3\text{-C}\equiv\text{N} + 2\text{H}_2\text{O} + \text{HCl} \longrightarrow \text{CH}_3\text{COOH} + \text{NH}_4\text{Cl} $$

Solution:

  • Methyl cyanide (\( \text{CH}_3\text{CN} \)) undergoes complete hydrolysis in the presence of water and \( \text{HCl} \).


  • The product is ethanoic acid (acetic acid) and ammonium chloride (\( \text{NH}_4\text{Cl} \)).


Why other options are incorrect:

Ammonia is formed only during base-catalyzed hydrolysis. Methyl chloride and acid amides are not the final stable products of complete acidic hydrolysis.

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