Chemistry Carboxylic Acids SET 2019
PMDC Verified Question 59 of 94
What will be the outcome of reaction of methanol with ethanoic acid in the presence of concentrated sulphuric acid?
A
Propanone is formed
B
Propanoic acid formed
C
Methyl ethanoate is formed
D
Propanol is formed
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: Methyl ethanoate is formed
Concept:

The acid-catalyzed condensation of an alcohol and a carboxylic acid produces an ester (Esterification).

Formula:

$$ \text{CH}_3\text{COOH} + \text{CH}_3\text{OH} \rightleftharpoons^+} \text{CH}_3\text{COOCH}_3 + \text{H}_2\text{O} $$

Solution:

  • The alcohol is methanol (providing the methyl group).


  • The acid is ethanoic acid (providing the ethanoate backbone).


  • Combining them forms the ester named methyl ethanoate.


Why other options are incorrect:

Propanone (a ketone), propanoic acid, and propanol require completely different reactants and non-esterification reaction pathways.

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