Chemistry Carboxylic Acids DUHS 2023
PMDC Verified Question 31 of 94
Which of the following is formed when formaldehyde is treated with oxidizing mixture? (\( \text{H}_2\text{SO}_4 + \text{K}_2\text{Cr}_2\text{O}_7 \))?
A
Methanol
B
Methanoic acid
C
Acetone
D
Acetaldehyde
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: Methanoic acid
Concept:

Aldehydes are highly susceptible to oxidation and are readily converted into their corresponding carboxylic acids (maintaining the same number of carbon atoms) when treated with strong oxidizing agents.

Formula:

$$ \text{HCHO} + [\text{O}] \xrightarrow{\text{K}_2\text{Cr}_2\text{O}_7 / \text{H}_2\text{SO}_4} \text{HCOOH} $$

Solution:

  • Formaldehyde (\( \text{HCHO} \)) contains exactly one carbon atom.


  • Acidified potassium dichromate is a strong oxidizing agent.


  • It inserts an oxygen atom into the aldehydic \( \text{C-H} \) bond, creating a carboxyl group (\( -\text{COOH} \)).


  • The 1-carbon carboxylic acid formed is methanoic acid (formic acid).


Why other options are incorrect:

Methanol would require reduction. Acetone (3 carbons) and Acetaldehyde (2 carbons) are impossible to form without adding carbon atoms to the framework.

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