Chemistry Chemical Bonding ETEA 2019
PMDC Verified Question 79 of 102
\( \text{Fe}^{+2} \) will form the most ionic bond with:
A
\( \text{N}^{-3} \)
B
\( \text{Sn}^{-3} \)
C
\( \text{P}^{-3} \)
D
\( \text{F}^{-1} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: \( \text{F}^{-1} \)
Concept:

The ionic character of a bond is directly proportional to the difference in electronegativity between the metal cation and the non-metal anion.

Formula:

$$ \text{Max } \Delta\text{EN} = \text{Most Ionic Character} $$

Solution:

  • Fluorine (\( \text{F}^{-1} \)) is the most electronegative element in the periodic table (EN = 4.0).


  • The difference in electronegativity between Iron and Fluorine will be the largest possible among the given choices.


  • Therefore, the bond between \( \text{Fe}^{+2} \) and \( \text{F}^{-1} \) will exhibit the highest percentage of ionic character.


Why other options are incorrect:

  • Option A, Option B, Option C: Nitrogen, Tin, and Phosphorus have significantly lower electronegativities than Fluorine, resulting in bonds with higher covalent character.

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