Chemistry Chemical Bonding ETEA 2019
PMDC Verified Question 82 of 102
Which equation relates to the first ionization energy of bromine?
A
\( \text{Br}_{2(g)} \longrightarrow \text{Br}^+_{(g)} + 1\text{e}^- \)
B
\( \text{Br}_{(g)} \longrightarrow \text{Br}^+_{(g)} + 1\text{e}^- \)
C
\( \frac{1}{2}\text{Br}_{2(g)} \longrightarrow \text{Br}^+_{(g)} + 1\text{e}^- \)
D
\( \frac{1}{2}\text{Br}_{2(l)} \longrightarrow \text{Br}^+_{(g)} + 1\text{e}^- \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( \text{Br}_{(g)} \longrightarrow \text{Br}^+_{(g)} + 1\text{e}^- \)
Concept:

By definition, first ionization energy is the energy required to remove one mole of electrons from one mole of isolated gaseous atoms to form gaseous cations.

Formula:

$$ X_{(g)} \longrightarrow X^+_{(g)} + e^- $$

Solution:

  • The definition strictly demands that the starting material is an isolated, single gaseous atom (\( \text{Br}_{(g)} \)), NOT a molecule.


  • Option B shows exactly this: a single, gaseous Bromine atom losing one electron to become a gaseous Bromine cation.


Why other options are incorrect:

  • Option A, Option C, Option D: These involve \( \text{Br}_2 \) molecules (either gaseous or liquid). Ionizing a molecule involves bond dissociation enthalpy and/or enthalpy of vaporization, which confounds the pure definition of atomic ionization energy.

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