Chemistry Chemical Bonding MDCAT 2019
PMDC Verified Question 84 of 102
In the second period of elements, although oxygen lies next to nitrogen yet its first ionization energy is lower than that of nitrogen because?
A
In oxygen, there exists repulsion between pair of electrons present in the same orbital of valence shell
B
Oxygen is paramagnetic in character.
C
Nuclear charge of oxygen is greater than nitrogen.
D
Oxygen has higher electron affinity.
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: In oxygen, there exists repulsion between pair of electrons present in the same orbital of valence shell
Concept:

Half-filled subshells (like Nitrogen's \( 2p^3 \)) provide extra stability. Adding one more electron creates pairing repulsion, making it easier to remove.

Formula:

$$ \text{N: } 2p^3 \text{ (stable)} \quad vs \quad \text{O: } 2p^4 \text{ (repulsion)} $$

Solution:

  • Nitrogen has a perfectly half-filled p-subshell, which is symmetrically stable.


  • Oxygen has four p-electrons, meaning one of the p-orbitals must contain a pair of electrons.


  • This pairing causes inter-electronic repulsion, destabilizing the electron and making it easier to remove from Oxygen than from the highly stable Nitrogen atom.


Why other options are incorrect:

  • Option C: A greater nuclear charge would logically increase ionization energy. The anomaly is purely due to electron repulsion.
  • Option B & Option D: True statements about Oxygen, but they do not explain the ionization energy anomaly.

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