Chemistry Chemical Bonding PMC 2021
PMDC Verified Question 60 of 102
P character in sp:
A
75%
B
50%
C
25%
D
33%
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: 50%
Concept:

The fractional character of a specific orbital type in a hybrid is determined by its ratio to the total number of orbitals involved.

Formula:

$$ \text{% p-character} = \left( \frac{\text{number of p orbitals}}{\text{total hybrid orbitals}} \right) \times 100 $$

Solution:

  • \( \text{sp} \) hybridization is formed by mixing one s-orbital and one p-orbital.


  • Total orbitals mixed = 2.


  • Ratio of p-orbitals = \( \frac{1}{2} \).


  • \( \frac{1}{2} \times 100 = 50\% \).


Why other options are incorrect:

  • Option A: 75% is the p-character of an \( \text{sp}^3 \) orbital.
  • Option C: 25% is the s-character of an \( \text{sp}^3 \) orbital.
  • Option D: 33% is the s-character of an \( \text{sp}^2 \) orbital.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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