Chemistry Chemical Bonding UHS 2022
PMDC Verified Question 40 of 102
\( \text{AB}_4 \) type with no lone pairs geometry enables to form which shape of molecule?
A
Trigonal
B
Regular octahedron
C
Regular tetrahedron
D
Regular pyramidal
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: Regular tetrahedron
Concept:

VSEPR theory dictates that 4 identical bonding domains around a central atom will orient themselves in 3D space to maximize their separation angles.

Formula:

$$ \text{Angle} = 109.5^{\circ} $$

Solution:

  • With 4 bond pairs and 0 lone pairs, the most stable, lowest-energy configuration is a perfect, symmetrical 3D tetrahedron.


  • Because all four domains are identical bonds, the geometry is a "Regular tetrahedron".


Why other options are incorrect:

  • Option A: Describes 3 bond domains.
  • Option B: Describes 6 bond domains.
  • Option D: Describes 3 bond domains + 1 lone pair.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

Previous Question All Chemical Bonding MCQs Next Question

Want to solve full-length papers under timed exam conditions?

Practice with zero-scroll lockdown sprints, dynamic latency zone timers, live peer selection telemetry, and the automated Amber mistake recovery loop.

Enter Arena Sprint iOS App Android App