Chemistry Chemical Bonding NUMS 2022
PMDC Verified Question 56 of 102
Type of hybridization of carbon in Ethene (\( \text{H}_2\text{C}=\text{CH}_2 \)) is:
A
\( \text{sp}^3 \)
B
\( \text{sp} \)
C
\( \text{sp}^2 \)
D
\( \text{dsp}^2 \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: \( \text{sp}^2 \)
Concept:

The hybridization of a carbon atom depends on the number of sigma bonds it forms.

Formula:

$$ \text{Steric Number (SN)} = \text{Number of } \sigma \text{ bonds} $$

Solution:

  • In Ethene (\( \text{C}_2\text{H}_4 \)), each Carbon atom is bonded to two Hydrogens (2 single sigma bonds) and one Carbon (1 double bond = 1 sigma + 1 pi).


  • Total sigma domains = 3.


  • A steric number of 3 requires the mixing of one s and two p orbitals, yielding \( \text{sp}^2 \) hybridization.


Why other options are incorrect:

  • Option A: Requires 4 sigma bonds (e.g., Ethane).
  • Option B: Requires 2 sigma bonds (e.g., Ethyne).
  • Option D: Involves d-orbitals, which carbon (in Period 2) does not possess in its valence shell.

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