Chemistry Chemical Bonding SZABMU 2024
PMDC Verified Question 4 of 102
Diamagnetic behavior of Fluorine molecule is due to presence of ____
A
Paired electrons in d orbitals
B
Paired electrons in p orbitals
C
Unpaired electrons in d orbitals
D
Unpaired electrons in p orbitals
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: Paired electrons in p orbitals
Concept:

Diamagnetism occurs when all electrons in a molecule's molecular orbitals are perfectly spin-paired, leaving no net magnetic field.

Formula:

$$ \text{F}_2 \text{ Molecular Orbital Configuration contains ONLY paired electrons.} $$

Solution:

  • A fluorine atom (Group 7) has its valence electrons strictly in s and p orbitals (\( 2s^2 \ 2p^5 \)). It has no access to d-orbitals.


  • When two F atoms bond to form \( \text{F}_2 \), their p-orbitals overlap to form molecular orbitals.


  • All 14 valence electrons perfectly fill the bonding and antibonding molecular orbitals in pairs.


  • Because all electrons residing in the p-derived molecular orbitals are paired, the molecule is repelled by magnetic fields (diamagnetic).


Why other options are incorrect:

  • Option A & Option C: Fluorine (Period 2) does not have d-orbitals.
  • Option D: Unpaired electrons would make the molecule paramagnetic (like \( \text{O}_2 \)), not diamagnetic.

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