Concept:When two half-cells are connected, the one with the higher (more positive) standard reduction potential acts as the cathode (undergoes reduction), and the other acts as the anode (undergoes oxidation).
Solution:- Copper has a standard reduction potential of \( +0.34 \text{ V} \), which is greater than that of SHE (\( 0.00 \text{ V} \)).
- Because Copper has a higher reduction potential, it forces the SHE to act as the anode.
- At the anode, oxidation (loss of electrons) occurs.
- The oxidation half-reaction for hydrogen gas is: \( H_{2(g)} \rightarrow 2H^+_{(aq)} + 2e^- \).
Why other options are incorrect:Option A represents reduction, which would only happen if SHE were connected to a metal with a negative reduction potential (like Zn). Option C is stoichiometrically incorrect. Option D shows the formation of atomic hydrogen gas instead of aqueous \( H^+ \) ions.
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