Chemistry Electrochemistry ETEA 2016
PMDC Verified Question 67 of 73
A cell is constructed of the following two half cells. What is Emf of the cell?

\( Ag^+ + e^- \rightleftharpoons Ag + 0.80V \)
\( Al^{+3} + 3e^- \rightleftharpoons Al - 1.67V \)
A
2.47V
B
0.087
C
-0.87 V
D
5.81 V
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: 2.47V
Concept:

The standard Electromotive Force (EMF) of a cell is calculated by subtracting the reduction potential of the anode from the reduction potential of the cathode.

Formula:

$$E^\circ_{cell} = E^\circ_{cathode} - E^\circ_{anode}$$

Solution:

  • First, identify the anode and cathode based on standard reduction potentials.


  • Ag has a higher reduction potential (\( +0.80 \text{ V} \)), so it acts as the cathode (reduction).


  • Al has a lower reduction potential (\( -1.67 \text{ V} \)), so it acts as the anode (oxidation).


  • Apply the formula: \( E^\circ_{cell} = (+0.80 \text{ V}) - (-1.67 \text{ V}) \).


  • \( E^\circ_{cell} = 0.80 + 1.67 = 2.47 \text{ V} \).


Why other options are incorrect:

If one incorrectly subtracted the larger from the smaller, they would get a negative voltage. Standard galvanic cell potentials are always positive.

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