Chemistry Equilibrium BUMHS 2024
PMDC Verified Question 28 of 102
Suppose the following system has reached equilibrium at a certain temperature

$$ \text{N}_2\text{O}_{4(g)} \rightleftharpoons 2\text{NO}_{2(g)} $$
Adding \( \text{N}_2\text{O}_4 \) to the system will
A
Start forward reaction
B
Start reverse reaction
C
Not disturb equilibrium
D
Raise the temperature of system
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: Start forward reaction
Concept:

According to Le Chatelier's Principle, adding more reactant to a system at equilibrium throws the system out of balance, forcing it to consume the excess.

Formula:

$$ Q_c = \frac{[\text{NO}_2]^2}{[\text{N}_2\text{O}_4]} $$

Solution:

  • By adding \( \text{N}_2\text{O}_4 \), you spike the concentration of the reactant (the denominator in the \( Q_c \) expression).


  • This makes \( Q_c < K_c \). The system is no longer at equilibrium.


  • To restore equilibrium, the system must reduce the denominator and increase the numerator by converting the excess \( \text{N}_2\text{O}_4 \) into \( \text{NO}_2 \).


  • This direction (left to right) is known as the forward reaction.


Why other options are incorrect:

Starting the reverse reaction would require adding product. It heavily disturbs equilibrium. Temperature changes are external stresses, not guaranteed products of this specific physical addition.

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