Chemistry Fundamental Principles of Organic Chemistry MDCAT 2018
PMDC Verified Question 69 of 83
In the following organic compound carbon atoms in all of them undergo both sp³ and sp² hybridization except X, which has all sp³ hybrid orbitals, identify X:
A
1-Butanol
B
Trans-2-butene
C
2-Chloro-2-butene
D
Butanoic acid
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: 1-Butanol
Concept:

Carbon atoms forming only single (sigma) bonds are sp³ hybridized. Carbon atoms forming one double bond are sp² hybridized.

Solution:

  • We must find the compound where all carbon atoms have solely single bonds.


  • Trans-2-butene (B) and 2-Chloro-2-butene (C) contain a \( \text{C}=\text{C} \) double bond (sp² carbons).


  • Butanoic acid (D) contains a \( \text{C}=\text{O} \) double bond in the carboxyl group (sp² carbon).


  • 1-Butanol (A) (\( \text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{OH} \)) contains only single bonds throughout the molecule. Therefore, every single carbon atom is sp³ hybridized.


Why other options are incorrect:

Options B, C, and D contain at least one sp² hybridized carbon due to the presence of double bonds.

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