Chemistry Gases MDCAT 2017
PMDC Verified Question 58 of 65
Identify the value of R at STP.
A
\( 8.314 \text{ atm dm}^3 \text{ mol}^{-1} \)
B
\( 0.0821 \text{ atm dm}^3 \text{ K}^{-1} \text{ mol}^{-1} \)
C
\( 0.0821 \text{ cal K}^{-1} \text{ mol}^{-1} \)
D
\( 8.314 \text{ cal K}^{-1} \text{ mol}^{-1} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( 0.0821 \text{ atm dm}^3 \text{ K}^{-1} \text{ mol}^{-1} \)
Concept:

The universal gas constant (R) is derived from the ideal gas equation \( R = \frac{PV}{nT} \). Its numerical value depends entirely on the units used for Pressure (P) and Volume (V).

Solution:

  • At Standard Temperature and Pressure (STP), \( P = 1 \text{ atm} \), \( T = 273.15 \text{ K} \), and for \( n = 1 \text{ mole} \), \( V = 22.414 \text{ dm}^3 \).


  • Substitute these into the equation: \( R = \frac{1 \text{ atm} \times 22.414 \text{ dm}^3}{1 \text{ mole} \times 273.15 \text{ K}} \).


  • Calculating this yields \( R \approx 0.0821 \text{ atm dm}^3 \text{ K}^{-1} \text{ mol}^{-1} \).


Why other options are incorrect:

  • Option A: 8.314 is the value of R in SI units (Joules), and the unit provided lacks Kelvin \( (\text{K}^{-1}) \).
  • Options C & D: The value of R in calories is approximately \( 1.987 \text{ cal K}^{-1} \text{ mol}^{-1} \), making these combinations incorrect.

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