Concept:Charles's Law establishes a direct, linear relationship between the volume of a gas and its absolute temperature. Extrapolating this line backward to where Volume = 0 yields the concept of absolute zero.
Formula:$$ V_t = V_o \left(1 + \frac{t^\circ C}{273.15}\right) $$
Solution:- In the equation, \( V_t \) is the volume at temperature \( t \), and \( V_o \) is the volume at 0°C.
- To find the temperature where volume theoretically becomes zero, set \( V_t = 0 \).
- \( 0 = V_o \left(1 + \frac{t}{273.15}\right) \). Since \( V_o \) is not zero, the term in parentheses must be zero.
- \( 1 + \frac{t}{273.15} = 0 \implies \frac{t}{273.15} = -1 \implies t = -273.15^\circ C \).
- This theoretical temperature is known as absolute zero (0 Kelvin).
Why other options are incorrect:- Options A, B, & D: These are random arbitrary temperatures well above absolute zero where gases still possess significant volume and kinetic energy.
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