Chemistry Gases DUHS 2022
PMDC Verified Question 40 of 65
The comparison of rate of diffusion of \( \text{H}_2 \) & \( \text{O}_2 \) is in the ratio of:
A
2:1
B
1:4
C
3:2
D
4:1
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: 4:1
Concept:

According to Graham's Law of Diffusion, the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.

Formula:

$$ \frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}} $$

Solution:

  • Identify the molar masses: \( M_{\text{H}_2} = 2 \text{ g/mol} \) and \( M_{\text{O}_2} = 32 \text{ g/mol} \).


  • Set up the ratio comparing Hydrogen (gas 1) to Oxygen (gas 2): \( \frac{r_{\text{H}_2}}{r_{\text{O}_2}} = \sqrt{\frac{M_{\text{O}_2}}{M_{\text{H}_2}}} \).


  • Substitute the values: \( \sqrt{\frac{32}{2}} = \sqrt{16} \).


  • Calculate the square root: \( \sqrt{16} = 4 \), which translates to a ratio of 4:1.


  • This means hydrogen diffuses 4 times faster than oxygen.


Why other options are incorrect:

  • Option A (2:1): This would only be true if \( M_{\text{O}_2} \) was 8.
  • Option B (1:4): This is the inverted ratio (Rate of \( \text{O}_2 \) to Rate of \( \text{H}_2 \)). The question asks for \( \text{H}_2 \) to \( \text{O}_2 \).
  • Option C (3:2): Mathematically unrelated to the molar masses 32 and 2.

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