Chemistry Hydrocarbons MDCAT 2017
PMDC Verified Question 44 of 65
Intermediate product formed when propanoyl chloride reacts with benzene is
A
Phenyl radical
B
Primary carbocation
C
Acylium ion
D
\( \sigma \)-complex (Benzenonium ion) bearing the acyl group
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: \( \sigma \)-complex (Benzenonium ion) bearing the acyl group
Concept:

In Friedel-Crafts acylation, the reaction proceeds through a distinct, non-aromatic cationic intermediate before restoring aromaticity.

Solution:

  • Propanoyl chloride reacts with a Lewis acid to form an acylium electrophile (\( \text{CH}_3\text{CH}_2\text{C}^+=\text{O} \)).


  • When the benzene pi ring attacks this electrophile, a resonance-stabilized carbocation is formed within the ring.


  • This intermediate—where one carbon becomes \( \text{sp}^3 \) hybridized holding both an H atom and the new acyl group—is called a \( \sigma \)-complex, arenium ion, or benzenonium ion.


Why other options are incorrect:

  • The acylium ion is the electrophile, but the actual intermediate product formed with benzene is the \( \sigma \)-complex.


  • A phenyl radical belongs to free radical mechanisms, not electrophilic substitution.


  • A simple primary carbocation is not formed in aromatic acylation.

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