Chemistry Hydrocarbons ETEA 2024
PMDC Verified Question 2 of 65
The homolytic fission of C-H bond in an alkane results
A
Alkyl free radical
B
Carbanion
C
Carbocation
D
Methylpropane
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: Alkyl free radical
Concept:

Bond cleavage occurs in two ways: heterolytic (unequal sharing of electrons) and homolytic (equal sharing of electrons).

Solution:

  • In an alkane, the C-H bond consists of two shared electrons.


  • When homolytic fission occurs (typically initiated by UV light or high heat), the bond breaks symmetrically.


  • The carbon atom takes one electron, and the hydrogen atom takes the other electron.


  • This produces a highly reactive, neutral species with an unpaired electron, known as an alkyl free radical.


Why other options are incorrect:

  • Carbanions (negative) and Carbocations (positive) are products of heterolytic fission, where both electrons go to one atom.


  • Methylpropane is a completely separate stable molecule, not an intermediate species.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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