Chemistry Liquids SZABMU 2022
PMDC Verified Question 34 of 73
The strongest hydrogen bond is present in:
A
\( \text{H}_2\text{S} \)
B
\( \text{HF} \)
C
\( \text{H}_2\text{O} \)
D
\( \text{NH}_3 \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( \text{HF} \)
Concept:

The strength of a single hydrogen bond is determined by the difference in electronegativity between the hydrogen atom and the atom it is bonded to.

Formula:

$$ \text{H-Bond Strength} \propto \Delta \text{E.N.} $$

Solution:

  • Fluorine is the most electronegative element (E.N. = 4.0).


  • The massive electronegativity difference in HF causes the hydrogen atom to become extremely electron-deficient (highly positive).


  • This highly positive hydrogen creates the strongest singular intermolecular electrostatic attraction (H-bond) observed in simple molecules.


  • Note: While water has a higher boiling point due to forming more H-bonds per molecule, the individual bond strength is highest in HF.


Why other options are incorrect:

Oxygen (3.5) and Nitrogen (3.0) are less electronegative than Fluorine. Hydrogen Sulfide (\( \text{H}_2\text{S} \)) practically does not form hydrogen bonds due to sulfur's larger size and lower electronegativity.

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