Chemistry Liquids BUMHS 2023
PMDC Verified Question 25 of 73
At room temperature, Glycerin boils at \( 290^\circ\text{C} \). What is the boiling point of Glycerin under vacuum distillation at 50 torr?
A
\( 320^\circ\text{C} \)
B
\( 310^\circ\text{C} \)
C
\( 300^\circ\text{C} \)
D
\( 210^\circ\text{C} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: \( 210^\circ\text{C} \)
Concept:

Vacuum distillation is utilized to lower the boiling point of liquids that might otherwise decompose at their normal, high boiling points by drastically reducing the external pressure.

Formula:

$$ P_{\text{external}} \downarrow \implies \text{Boiling Point} \downarrow $$

Solution:

  • Under normal atmospheric pressure (760 torr), glycerin boils at \( 290^\circ\text{C} \). At this high temperature, it actually begins to chemically decompose.


  • By applying a vacuum and reducing the external pressure all the way down to just 50 torr, the vapor pressure of glycerin matches the external pressure much sooner.


  • Experimentally (and classically taught in standard textbooks), at 50 torr, the boiling point of glycerin safely drops to \( 210^\circ\text{C} \), allowing it to be distilled without degradation.


Why other options are incorrect:

Options A, B, and C represent temperatures higher than the normal boiling point, which would require an increase in external pressure, completely contradicting the premise of vacuum distillation.

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