Chemistry S & P Block Elements MDCAT 2015
PMDC Verified Question 92 of 104
Which one of the following will have the smallest radius?
A
\( \text{Al}^{+3} \)
B
\( \text{Mg}^{+2} \)
C
\( \text{Si}^{+4} \)
D
\( \text{Na}^{+1} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: \( \text{Si}^{+4} \)
Concept:

For purely isoelectronic species (ions with the same number of electrons), the ionic radius is inversely proportional to the magnitude of the positive charge (or nuclear charge).

Formula:

$$ \text{Ionic Radius} \propto \frac{1}{\text{Nuclear Charge (Protons)}} $$

Solution:

  • All given ions are isoelectronic, containing exactly 10 electrons (configuration of Neon: \( 1s^2 2s^2 2p^6 \)).
  • The number of protons pulling on these 10 electrons are: Na (11), Mg (12), Al (13), Si (14).
  • \( \text{Si}^{+4} \) has the highest nuclear charge (+14).
  • The stronger nuclear pull draws the remaining electrons much closer, resulting in the hypothetically smallest cationic radius.


Why other options are incorrect:

  • The other ions have fewer protons, meaning their nucleus exerts a weaker pull on the 10 electrons, leaving their ionic radii comparatively larger than \( \text{Si}^{+4} \).

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