Chemistry S & P Block Elements UHS 2022
PMDC Verified Question 46 of 104
Why dimer of \( \text{AlCl}_3 \) is formed
A
Al is electron rich
B
Al is having lone pair of electron
C
Al donates lone pair to form bridge
D
Al forms co-ordinate bonds with chlorine to complete its octet
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Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: Al forms co-ordinate bonds with chlorine to complete its octet
Concept:

Molecules with incomplete valence shells (electron-deficient) will undergo structural rearrangement to achieve a stable octet, often forming coordinate covalent (dative) bonds.

Solution:

  • In a single molecule of Aluminum chloride (\( \text{AlCl}_3 \)), the central Aluminum atom forms 3 covalent bonds with 3 Chlorine atoms.
  • This means Aluminum only has 6 electrons in its valence shell (it is electron-deficient and lacks a full octet).
  • To achieve stability, two \( \text{AlCl}_3 \) molecules join together to form a dimer (\( \text{Al}_2\text{Cl}_6 \)).
  • A Chlorine atom from one molecule uses its lone pair to form a coordinate covalent bond with the electron-deficient Aluminum of the other molecule, and vice versa.
  • This mutually completes the octet for both Aluminum atoms.


Why other options are incorrect:

  • Option A & B: Aluminum is electron-deficient in \( \text{AlCl}_3 \), not electron-rich, and it has absolutely no lone pairs to donate.
  • Option C: It is the Chlorine atom that donates the lone pair, not the Aluminum.

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