Chemistry S & P Block Elements SZABMU 2024
PMDC Verified Question 8 of 104
When potassium superoxide reacts with carbon dioxide, following products are formed
A
\( \text{K}_2\text{CO}_3 \) + \( \text{O}_2 \)
B
\( \text{KO}_2 \) + \( \text{O}_2 \) + [O]
C
\( \text{K}_2\text{CO}_3 \) + \( \text{CO}_2 \)
D
\( \text{KO}_2 \) + \( \text{CO}_2 \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: \( \text{K}_2\text{CO}_3 \) + \( \text{O}_2 \)
Concept:

Potassium superoxide (\( \text{KO}_2 \)) has a highly unique chemical property: it absorbs carbon dioxide and simultaneously releases pure oxygen gas.

Solution:

  • Because of this specific reaction, \( \text{KO}_2 \) is widely used in closed-loop breathing apparatuses (like submarines and spacesuits).
  • The chemical reaction involves the superoxide reacting with \( \text{CO}_2 \) to form solid potassium carbonate and gaseous oxygen.
  • The balanced chemical equation is:

    $$ 4\text{KO}_2 + 2\text{CO}_2 \longrightarrow 2\text{K}_2\text{CO}_3 + 3\text{O}_2 $$

  • Therefore, the distinct products are Potassium carbonate (\( \text{K}_2\text{CO}_3 \)) and Oxygen (\( \text{O}_2 \)).


Why other options are incorrect:

  • The other options do not show the conversion of the superoxide into carbonate, nor do they account for the vital release of \( \text{O}_2 \) gas.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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