Chemistry S & P Block Elements BUMHS 2024
PMDC Verified Question 20 of 104
Sodium nitrate (\( \text{NaNO}_3 \)), on heating, decomposes forming
A
\( \text{Na}_2\text{O} \) and \( \text{NO}_2 \)
B
\( \text{NaNO}_2 \) and \( \text{O}_2 \)
C
Na, \( \text{NO}_2 \) and \( \text{O}_2 \)
D
\( \text{Na}_2\text{O}_3 \), \( \text{NO}_2 \) and \( \text{O}_2 \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( \text{NaNO}_2 \) and \( \text{O}_2 \)
Concept:

The thermal decomposition products of metal nitrates depend on the reactivity of the metal. Alkali metal nitrates (except Lithium) decompose differently than heavy metal nitrates.

Formula:

$$ 2\text{NaNO}_{3(s)} \xrightarrow{\Delta} 2\text{NaNO}_{2(s)} + \text{O}_{2(g)} $$

Solution:

  • When heavy metal nitrates (like Lead or Copper) are heated, they decompose completely into the metal oxide, nitrogen dioxide gas, and oxygen gas.
  • However, Sodium is a highly reactive Group 1 alkali metal.
  • When Sodium nitrate (\( \text{NaNO}_3 \)) is heated, it undergoes a partial decomposition. It melts and releases oxygen gas, leaving behind a stable salt, Sodium nitrite (\( \text{NaNO}_2 \)).
  • Therefore, the products are strictly \( \text{NaNO}_2 \) and \( \text{O}_2 \).


Why other options are incorrect:

  • Option A describes the decomposition pattern of a less reactive metal (like Copper). Options C and D list chemically unrealistic or unstable decomposition products for this reaction.

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