Chemistry Stoichiometry MDCAT 2011
PMDC Verified Question 103 of 105
How many chlorine atoms are in 2 moles of Cl?
A
\( 2 \times 6.022 \times 10^{23} \text{ atoms} \)
B
\( 35.5 \times 6.022 \times 10^{23} \text{ atoms} \)
C
\( 2 \times 10^{23} \text{ atoms} \)
D
\( 2 \times 6.02 \times 10^{22} \text{ atoms} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: \( 2 \times 6.022 \times 10^{23} \text{ atoms} \)
Concept:

A mole is defined as the amount of substance that contains Avogadro's number (\( N_A \)) of particles (atoms, molecules, or ions).

Formula:

$$ \text{Number of atoms} = n \times N_A $$

Solution:

  • We are given \( n = 2 \text{ moles} \) of atomic Chlorine (Cl).


  • Avogadro's number \( N_A = 6.022 \times 10^{23} \).


  • Total atoms = \( 2 \times (6.022 \times 10^{23}) \text{ atoms} \).


Why other options are incorrect:

  • Option B: Multiplies Avogadro's number by the molar mass (35.5), which calculates total mass, not the number of atoms.


  • Option C: Omits Avogadro's constant entirely.


  • Option D: Has an incorrect power of ten (\( 10^{22} \) instead of \( 10^{23} \)).

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