Chemistry Stoichiometry BUMHS 2023
PMDC Verified Question 42 of 105
How many moles of a gas occupy 30.57 L at \( 55^\circ\text{C} \) and 0.83 atm?
A
0.1 mol
B
0.62 mol
C
0.84 mol
D
0.94 mol
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: 0.94 mol
Concept:

When dealing with non-standard conditions (not STP), we must use the Ideal Gas Law to link Pressure, Volume, Temperature, and Moles.

Formula:

$$ PV = nRT \rightarrow n = \frac{PV}{RT} $$

Solution:

  • Pressure (P) = 0.83 atm.


  • Volume (V) = 30.57 L.


  • Temperature (T) = \( 55^\circ\text{C} + 273 = 328 \text{ K} \).


  • Universal Gas Constant (R) = 0.0821 L atm / (mol K).


  • Substitute: \( n = \frac{0.83 \times 30.57}{0.0821 \times 328} \).


  • Numerator: \( 0.83 \times 30.57 \approx 25.37 \).


  • Denominator: \( 0.0821 \times 328 \approx 26.93 \).


  • \( n = 25.37 / 26.93 \approx 0.94 \text{ moles} \).


Why other options are incorrect:

  • 0.1, 0.62, 0.84 mol: These values result from forgetting to convert Celsius to Kelvin, or using an incorrect value for the Gas Constant 'R' (such as 8.314, which applies strictly to J/mol K and cubic meters, not Liters and atm).

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

Want to solve full-length papers under timed exam conditions?

Practice with zero-scroll lockdown sprints, dynamic latency zone timers, live peer selection telemetry, and the automated Amber mistake recovery loop.