Chemistry Thermochemistry MDCAT 2012
PMDC Verified Question 76 of 81
\( \Delta H \) will be given a negative sign in:
A
Dissociation reactions
B
Decomposition reactions
C
Exothermic reactions
D
Endothermic reactions
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: Exothermic reactions
Concept:

The change in enthalpy (\( \Delta H \)) represents the heat absorbed or released by a system at constant pressure. The sign convention is determined by the direction of heat flow.

Formula:

$$ \Delta H = H_{\text{products}} - H_{\text{reactants}} $$

Solution:

  • In an exothermic reaction, the system loses heat to the surroundings.


  • Because the energy of the products is lower than the energy of the reactants, the final enthalpy is less than the initial enthalpy.


  • Mathematically, this results in a negative value: \( \Delta H = -ve \).


Why other options are incorrect:

Endothermic, dissociation, and decomposition reactions generally require an input of energy to break chemical bonds, meaning they absorb heat from the surroundings and have a positive \( \Delta H \).

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