Chemistry Thermochemistry SET 2019
PMDC Verified Question 61 of 81
For a given reaction \( CH_3COOH + NaOH \rightarrow CH_3COONa + H_2O \) the change in enthalpy under standard conditions is called?
A
Standard enthalpy of neutralization
B
Standard enthalpy change of solution
C
Standard enthalpy change of formation
D
Standard enthalpy change of hydration
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: Standard enthalpy of neutralization
Concept:

A reaction between an acid and a base that produces a salt and water is known as a neutralization reaction. The heat released during this process is classified accordingly.

Formula:

$$ \text{Acid} + \text{Base} \rightarrow \text{Salt} + H_2O \quad (\Delta H = \Delta H_n^\circ) $$

Solution:

  • \( CH_3COOH \) is acetic acid (a weak acid) and \( NaOH \) is sodium hydroxide (a strong base).


  • They undergo a double displacement reaction to form sodium acetate (a salt) and one mole of water.


  • The enthalpy change associated with forming 1 mole of water from the reaction of \( H^+ \) and \( OH^- \) ions is defined precisely as the Standard enthalpy of neutralization.


Why other options are incorrect:

It is not a formation reaction (which requires elemental reactants). It is not a solution or hydration process because those involve dissolving a solute in a solvent, not a chemical acid-base reaction.

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