Chemistry Thermochemistry NUMS 2022
PMDC Verified Question 47 of 81
Specific heat of water is:
A
\( 8.47 \text{ J/g/}^\circ\text{C} \)
B
\( 4.18 \text{ J/g/}^\circ\text{C} \)
C
\( 6.04 \text{ J/g/}^\circ\text{C} \)
D
\( 9.82 \text{ J/g/}^\circ\text{C} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( 4.18 \text{ J/g/}^\circ\text{C} \)
Concept:

Specific heat capacity (c) is the amount of heat energy required to raise the temperature of exactly one gram of a substance by one degree Celsius (or one Kelvin).

Formula:

$$ c_{\text{water}} = 4.18 \text{ J } g^{-1} ^\circ C^{-1} $$

Solution:

  • Water has an exceptionally high specific heat capacity due to the extensive network of strong intermolecular hydrogen bonds holding the molecules together.


  • Experimentally, it takes exactly 1 calorie of energy to raise 1g of water by 1°C.


  • Since 1 calorie = 4.18 Joules, the specific heat of water is \( 4.18 \text{ J/g/}^\circ\text{C} \).


Why other options are incorrect:

Options A, C, and D are random numerical values that do not correspond to the known physical properties of liquid water.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

Want to solve full-length papers under timed exam conditions?

Practice with zero-scroll lockdown sprints, dynamic latency zone timers, live peer selection telemetry, and the automated Amber mistake recovery loop.