Chemistry Thermochemistry SZABMU 2024
PMDC Verified Question 8 of 81
Calculate \( \Delta H \) for the reaction:

A B C D ΔH_direct (A → B) ΔH_1 (-540) ΔH_2 (+200) ΔH_3 (-100)

(Note: The cycle describes a path from A to B directly, or indirectly via C and D: A → C → D → B. Where \( A ightarrow C = -540 ext{ kJ} \), \( C ightarrow D = +200 ext{ kJ} \), \( D ightarrow B = -100 ext{ kJ} \))
A
\( -400 \text{ KJ/mol} \)
B
\( -600 \text{ KJ/mol} \)
C
\( -440 \text{ KJ/mol} \)
D
\( -640 \text{ KJ/mol} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: \( -440 \text{ KJ/mol} \)
Concept:

Hess's Law states that the overall enthalpy change of a reaction is equal to the algebraic sum of the enthalpy changes of individual steps in a thermodynamic cycle, provided the initial and final states are identical.

Formula:

$$ \Delta H_{A \rightarrow B} = \Delta H_{A \rightarrow C} + \Delta H_{C \rightarrow D} + \Delta H_{D \rightarrow B} $$

Solution:

  • We want to find the direct route enthalpy from state A to state B.


  • The indirect route provides three sequential steps:


  • Step 1 (A to C): \( -540 \text{ kJ/mol} \)


  • Step 2 (C to D): \( +200 \text{ kJ/mol} \)


  • Step 3 (D to B): \( -100 \text{ kJ/mol} \)


  • Summing the steps: \( (-540) + 200 + (-100) = -640 + 200 = -440 \text{ kJ/mol} \).


Why other options are incorrect:

The other options are mathematically incorrect sums, resulting from incorrectly flipping signs or ignoring one of the sequence steps.

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