Chemistry Thermochemistry ETEA 2024
PMDC Verified Question 10 of 81
Calculate the work done when 1 mole of an ideal gas expands from \( 15 \text{ dm}^3 \) to \( 20 \text{ dm}^3 \) against a constant external pressure of 2 atmospheres.
A
\( -5 \text{ atm.dm}^3 \)
B
\( 5 \text{ atm.dm}^3 \)
C
\( 10 \text{ atm.dm}^3 \)
D
\( -10 \text{ atm.dm}^3 \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: \( 10 \text{ atm.dm}^3 \)
Concept:

The mechanical work done during the expansion or compression of a gas is calculated using pressure-volume formulas. Depending on the convention (physics vs. chemistry), the absolute magnitude is identical.

Formula:

$$ W = P \times \Delta V $$

Solution:

  • The constant external pressure (\( P \)) = 2 atmospheres.


  • The change in volume (\( \Delta V \)) = \( V_{\text{final}} - V_{\text{initial}} = 20 - 15 = 5 \text{ dm}^3 \).


  • Work magnitude = \( 2 \text{ atm} \times 5 \text{ dm}^3 = 10 \text{ atm.dm}^3 \).


  • Note: In standard IUPAC chemistry convention, expansion work is done by the system and is technically negative (\( -10 \text{ atm.dm}^3 \)). However, the ETEA key and provided options utilize the absolute magnitude / physics convention yielding a positive \( 10 \text{ atm.dm}^3 \).


Why other options are incorrect:

Values of 5 or -5 arise if the pressure is completely ignored or misapplied.

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