Physics Alternating Current PMDC Conceptual Practice
PMDC Verified Question 5 of 127
The frequency of an applied alternating current is \( 2\text{ kHz} \). What is its time period \( T \)?
A
\(0.5\text{ s}\)
B
\(5\text{ s}\)
C
\(0.5 \times 10^{-3}\text{ s}\)
D
\(2\text{ s}\)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: \(0.5 \times 10^{-3}\text{ s}\)
Concept:

The time period \( T \) is the reciprocal of the frequency \( f \).

Formula:

$$T = \frac{1}{f}$$

Solution:

Given frequency \( f = 2\text{ kHz} = 2 \times 10^3\text{ Hz} \):

$$T = \frac{1}{2 \times 10^3} = 0.5 \times 10^{-3}\text{ seconds} \quad (\text{or } 0.5\text{ ms})$$

Why other options are incorrect:

  • Other values are arithmetic errors resulting from failing to convert the "kilo" metric prefix (multiplying by 1000) or dividing incorrectly.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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