Physics Alternating Current PMC 2021
PMDC Verified Question 81 of 127

If the peak voltage of an AC signal is \( 9\text{ V} \), the corresponding peak-to-peak voltage of the waveform is:
A
9 V
B
18 V
C
4.5 V
D
0 V
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: 18 V
Concept:

This covers the conversion between peak voltage (amplitude) and peak-to-peak voltage for a symmetric alternating wave.

Formula:

$$V_{p-p} = 2 V_p$$

Solution:

Given \( V_p = 9\text{ V} \):

$$V_{p-p} = 2 \times 9\text{ V} = 18\text{ V}$$

Why other options are incorrect:

  • 4.5 V is the result of dividing by 2 instead of multiplying.


  • 9 V is simply the peak amplitude.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

Want to solve full-length papers under timed exam conditions?

Practice with zero-scroll lockdown sprints, dynamic latency zone timers, live peer selection telemetry, and the automated Amber mistake recovery loop.