Concept:Photon energy is directly proportional to frequency and inversely proportional to wavelength across the electromagnetic spectrum.
Formula / Reaction:$$E = hf = \frac{hc}{\lambda}$$
Solution:- The electromagnetic spectrum in order of increasing frequency and photon energy is: Radio \(\to\) Microwaves \(\to\) Infrared \(\to\) Visible \(\to\) UV \(\to\) X-rays \(\to\) Gamma rays.
- Gamma rays possess the highest frequencies (\(f > 10^{19}\text{ Hz}\)) and therefore the most energetic photons in the electromagnetic spectrum.
Why other options are incorrect:- Opt_A: Visible light photons have low energies (\(1.8\text{ to }3.1\text{ eV}\)).
- Opt_B: X-rays have high energy (\(\text{keV}\)), but are less energetic than nuclear gamma rays.
- Opt_C: Ultraviolet photons are lower in energy than X-rays and gamma rays.
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