Physics Alternating Current PMDC Conceptual Practice
PMDC Verified Question 67 of 127
What is the frequency of yellow visible light having a wavelength of \(600\text{ nm}\) in vacuum?
A
\(5.0 \times 10^{12}\text{ Hz}\)
B
\(2.0 \times 10^{14}\text{ Hz}\)
C
\(5.0 \times 10^{14}\text{ Hz}\)
D
\(1.8 \times 10^{15}\text{ Hz}\)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: \(5.0 \times 10^{14}\text{ Hz}\)
Concept:

Frequency is calculated from the wave speed equation \(f = \frac{c}{\lambda}\).

Formula / Reaction:

$$f = \frac{c}{\lambda}$$

Solution:

  • Given: \(c = 3.0 \times 10^8\text{ m/s}\), \(\lambda = 600\text{ nm} = 600 \times 10^{-9}\text{ m} = 6.0 \times 10^{-7}\text{ m}\).


  • \(f = \frac{3.0 \times 10^8}{6.0 \times 10^{-7}} = 0.5 \times 10^{15} = 5.0 \times 10^{14}\text{ Hz}\).


Why other options are incorrect:

  • Opt_A: Metric prefix error (\(10^{12}\)).


  • Opt_B: Inverted calculation error.


  • Opt_D: \(1.8 \times 10^{15}\text{ Hz}\) corresponds to ultraviolet radiation.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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