Physics Alternating Current PMDC Conceptual Practice
PMDC Verified Question 72 of 127
An AC voltmeter connected across a domestic AC line reads \(240\text{ V}\). What is the peak voltage \(V_0\) of this electrical supply?
A
\(339.4\text{ V}\)
B
\(240.0\text{ V}\)
C
\(169.7\text{ V}\)
D
\(480.0\text{ V}\)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: \(339.4\text{ V}\)
Concept:

AC measuring meters record root-mean-square values. Peak voltage is \(V_0 = \sqrt{2} V_{\text{rms}}\).

Formula / Reaction:

$$V_0 = \sqrt{2} V_{\text{rms}} = 1.4142 \times 240\text{ V}$$

Solution:

  • \(V_0 = 1.4142 \times 240 \approx 339.4\text{ V}\).


Why other options are incorrect:

  • Opt_B: \(240.0\text{ V}\) is the RMS reading.


  • Opt_C: \(169.7\text{ V}\) divides by \(\sqrt{2}\).


  • Opt_D: \(480.0\text{ V}\) doubles the RMS voltage.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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