Physics Atomic Spectra BUMHS 2024
PMDC Verified Question 6 of 21
According to the Bohr's model of an atom, the radius of the \( n^{\text{th}} \) orbit is proportional to:
A
\( n \)
B
\( \sqrt{n} \)
C
\( n^2 \)
D
\( n^3 \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: \( n^2 \)
Concept: Niels Bohr derived the radius of atomic orbits by combining classical mechanics (centripetal force matching electrostatic force) with his quantum postulate regarding angular momentum.

Formula:
$$ r_n = \frac{n^2 h^2}{4\pi^2 k m e^2} $$

Solution:
  • In the formula above, all terms except \( n \) (Planck's constant \( h \), Coulomb's constant \( k \), electron mass \( m \), and elementary charge \( e \)) are fundamental constants for a given atom.
  • Grouping these constants together yields: \( r_n = (\text{constant}) \times n^2 \).
  • For hydrogen, this simplifies to \( r_n = 0.529\text{\AA} \times n^2 \).
  • Therefore, the radius scales quadratically; it is strictly proportional to \( n^2 \).


Why other options are incorrect:
Options A, B, and D misrepresent the algebraic derivation. If the radius was simply proportional to \( n \), the quantum spacing of atoms would be strictly linear rather than expanding vastly outward.

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