Physics Current Electricity PMDC 2021
PMDC Verified Question 76 of 112
A load of resistance 0.04 \(\Omega\) is attached to the cell having E.M.F 1.5 V and 15 A is drawn in the circuit. The internal resistance of cell will be
A
0.6 \(\Omega\)
B
0.06 \(\Omega\)
C
6 \(\Omega\)
D
0.3 \(\Omega\)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: 0.06 \(\Omega\)
Concept:

The total resistance of a circuit includes both external load resistance and the internal resistance of the battery.

Formula:

$$ I = \frac{E}{R + r} $$

Solution:

  • Given \( I = 15 \text{ A} \), \( E = 1.5 \text{ V} \), \( R = 0.04 \, \Omega \).


  • Rearrange for total resistance: \( R + r = \frac{E}{I} \).


  • \( 0.04 + r = \frac{1.5}{15} = 0.1 \, \Omega \).


  • \( r = 0.1 - 0.04 = 0.06 \, \Omega \).


Why other options are incorrect:

  • Opt A: Decimal error (0.1 - 0.04 is not 0.6).


  • Opt C: Drastic decimal misplacement.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

Want to solve full-length papers under timed exam conditions?

Practice with zero-scroll lockdown sprints, dynamic latency zone timers, live peer selection telemetry, and the automated Amber mistake recovery loop.