Physics Electromagnetism MDCAT 2018
PMDC Verified Question 45 of 58
A neutron having mass equal to a proton (\( m_p = 1.6 \times 10^{-27} \ \text{kg} \)) is moving in a magnetic field of intensity \( 1.20 \times 10^{-3} \ \text{T} \) with a speed of \( 2.0 \times 10^7 \ \text{ms}^{-1} \) what is the Maximum force experienced by the neutron.
A
\( 3.84 \times 10^{-15} \ \text{N} \)
B
\( 0 \ \text{N} \)
C
\( 3.84 \times 10^{12} \ \text{N} \)
D
\( 38.4 \times 10^{-15} \ \text{N} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( 0 \ \text{N} \)
Concept:

The magnetic force acting on a particle depends fundamentally on the electric charge of that particle. Neutral particles do not interact with magnetic fields in this manner.

Formula:

$$ F = qvB \sin(\theta) $$

Solution:

  • Identify the particle: A neutron.


  • Recall the charge of a neutron: \( q = 0 \ \text{C} \).


  • Substitute this into the Lorentz force equation: \( F = (0) \cdot vB \sin(\theta) \).


  • Therefore, regardless of velocity or magnetic field strength, the magnetic force is exactly 0 N.


Why other options are incorrect:

Options A, C, and D are calculated by falsely assuming the neutron has the charge of a proton (\( 1.6 \times 10^{-19} \ \text{C} \)) and running the numbers.

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