Concept:Units in electromagnetism can be heavily intertwined using work, force, and current relationships. The Weber can be derived down to energy and current.
Formula:$$ \Phi = B \cdot A \quad \text{and} \quad W = F \cdot d $$
Solution:- Start with the base definition: \( 1 \ \text{Weber} = 1 \ \text{Tesla} \cdot \text{m}^2 \).
- Expand Tesla: \( \text{Weber} = \left( \frac{\text{N}}{\text{A \cdot m}} \right) \cdot \text{m}^2 = \frac{\text{N \cdot m}}{\text{A}} \).
- Recall that \( 1 \ \text{Newton} \cdot \text{meter} \) is the unit of mechanical work, the Joule (\( \text{J} \)).
- Substitute Joule in: \( 1 \ \text{Weber} = \frac{\text{Joule}}{\text{Ampere}} \).
Why other options are incorrect:Option B is the definition of a Volt. Option C is incomplete (missing the meter to make it a Joule). Option D is the unit for the Electric Field.
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