Physics Electronics PMDC 2021
PMDC Verified Question 471 of 494
Ripple factor of full wave rectifier?
A
1.21
B
0.84
C
0.482
D
0.21
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: 0.482
Concept:

Ripple factor mathematically describes the ratio of the RMS value of the AC component to the DC component in the output.

Formula:

$$ R.F = \sqrt{(F.F)^2 - 1} $$

Solution:

  • The Form Factor (\( F.F \)) for a full-wave rectifier is \( \frac{I_{rms}}{I_{DC}} = \frac{\pi}{2\sqrt{2}} \approx 1.11 \).


  • Substitute this into the ripple factor formula: \( R.F = \sqrt{(1.11)^2 - 1} \).


  • \( R.F = \sqrt{1.2321 - 1} = \sqrt{0.2321} \approx 0.482 \).


Why other options are incorrect:

  • \( 1.21 \): This is the ripple factor for a half-wave rectifier.


  • \( 0.84 \) & \( 0.21 \): These are incorrect distractors not tied to standard rectifier outputs.

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