Physics Electronics MDCAT 2000
PMDC Verified Question 484 of 494
Consider the circuit diagram below representing a forward-biased silicon diode:

p (+)n (−)\(I_{\text{forward}}\)

In this forward-biased \(\text{p-n}\) junction, the electric current is predominantly transported across the junction by:
A
Minority carriers moving under a strong built-in field
B
Majority carriers diffusing across the junction barrier
C
Electrons tunneling directly through the forbidden bandgap
D
Thermionic emission of electrons from the metal contacts
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: Majority carriers diffusing across the junction barrier
Concept:

In forward bias, external energy lowers the potential barrier, allowing majority carriers (holes from the p-side and electrons from the n-side) to diffuse across the junction, recombining as they enter the opposite regions and establishing a large forward current.

Formula:

$$I = I_s \left( e^{\frac{qV}{\eta k_B T}} - 1 \right)$$

Solution:

  • Forward bias lowers the built-in potential barrier from \(V_0\) to \((V_0 - V)\).


  • Majority holes in the p-region and majority electrons in the n-region obtain sufficient thermal energy to overcome the reduced barrier and diffuse across the junction.


  • Thus, forward current is primarily a majority carrier diffusion current.


Why other options are incorrect:

  • Option A: Minority carriers moving under the junction field cause reverse saturation leakage current.
  • Option C: Direct bandgap tunneling is significant only in heavily doped Zener/tunnel diodes, not standard forward-biased diodes.
  • Option D: Thermionic emission is the operating principle of vacuum tubes, not solid-state \(\text{p-n}\) junctions.

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