Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 22 of 494
When an intrinsic semiconductor crystal is heated, how do the concentrations of free electrons and holes change?
A
Electrons increase while holes decrease
B
Holes increase while electrons decrease
C
Both electron and hole concentrations increase equally
D
Both electron and hole concentrations remain constant
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: Both electron and hole concentrations increase equally
Concept:

In an intrinsic semiconductor, thermal energy breaks covalent bonds in the crystal lattice. Each broken bond generates exactly one free conduction electron and leaves behind exactly one vacancy (hole).

Formula:

$$n_i = p_i = A T^{3/2} e^{-\frac{E_g}{2 k_B T}}$$

Solution:

  • Thermal generation creates electron-hole pairs in equal numbers.


  • As temperature increases, more covalent bonds break, increasing the concentrations of both electrons (\(n\)) and holes (\(p\)) identically: \(\Delta n = \Delta p\).


  • This explains why semiconductors have a negative temperature coefficient of resistance.


Why other options are incorrect:

  • Option A: Electrons and holes are created in pairs; one carrier cannot increase while the other decreases upon heating.
  • Option B: Violates the conservation of charge and pair-generation physics in intrinsic semiconductors.
  • Option D: Carrier concentrations are strongly temperature-dependent, not constant.

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